Iridium Ionization Energy

The Iridium Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Iridium.
Ir -> Ir⁺ + e^-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Iridium is:
Ir^N+ -> Ir^(N+1)+ + e^-

Ir -> Ir¹⁺ = 880 kJ/mol = 210.53 Kcal/mol
Ir¹⁺ -> Ir²⁺ = 1680 kJ/mol = 401.91 Kcal/mol
Ir²⁺ -> Ir³⁺ = 2600 kJ/mol = 622.01 Kcal/mol
Ir³⁺ -> Ir⁴⁺ = 3800 kJ/mol = 909.09 Kcal/mol
Ir⁴⁺ -> Ir⁵⁺ = 5500 kJ/mol = 1315.79 Kcal/mol
Ir⁵⁺ -> Ir⁶⁺ = 6900 kJ/mol = 1650.72 Kcal/mol
Ir⁶⁺ -> Ir⁷⁺ = 8500 kJ/mol = 2033.49 Kcal/mol
Ir⁷⁺ -> Ir⁸⁺ = 10000 kJ/mol = 2392.34 Kcal/mol
Ir⁸⁺ -> Ir⁹⁺ = 11700 kJ/mol = 2799.04 Kcal/mol