Atomistry » Iridium » Energy
Atomistry »
  Iridium »
    Energy »

Iridium Ionization Energy

The Iridium Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Iridium.
Ir -> Ir+ + e-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Iridium is:
IrN+ -> Ir(N+1)+ + e-

Ionization Energy

Ir -> Ir1+ = 880 kJ/mol = 210.53 Kcal/mol
Ir1+ -> Ir2+ = 1680 kJ/mol = 401.91 Kcal/mol
Ir2+ -> Ir3+ = 2600 kJ/mol = 622.01 Kcal/mol
Ir3+ -> Ir4+ = 3800 kJ/mol = 909.09 Kcal/mol
Ir4+ -> Ir5+ = 5500 kJ/mol = 1315.79 Kcal/mol
Ir5+ -> Ir6+ = 6900 kJ/mol = 1650.72 Kcal/mol
Ir6+ -> Ir7+ = 8500 kJ/mol = 2033.49 Kcal/mol
Ir7+ -> Ir8+ = 10000 kJ/mol = 2392.34 Kcal/mol
Ir8+ -> Ir9+ = 11700 kJ/mol = 2799.04 Kcal/mol

Last articles

Zn in 7RRP
Zn in 7OKY
Zn in 7OL0
Zn in 7OKX
Zn in 7ONB
Zn in 7RSF
Zn in 7OUF
Zn in 7OUG
Zn in 7OUH
Zn in 7RGN
© Copyright 2008-2020 by atomistry.com
Home   |    Site Map   |    Copyright   |    Contact us   |    Privacy