The Iridium Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Iridium.
Ir -> Ir+ + e-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Iridium is:
IrN+ -> Ir(N+1)+ + e-
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Ir -> Ir1+ = 880 kJ/mol = 210.53 Kcal/mol
Ir1+ -> Ir2+ = 1680 kJ/mol = 401.91 Kcal/mol
Ir2+ -> Ir3+ = 2600 kJ/mol = 622.01 Kcal/mol
Ir3+ -> Ir4+ = 3800 kJ/mol = 909.09 Kcal/mol
Ir4+ -> Ir5+ = 5500 kJ/mol = 1315.79 Kcal/mol
Ir5+ -> Ir6+ = 6900 kJ/mol = 1650.72 Kcal/mol
Ir6+ -> Ir7+ = 8500 kJ/mol = 2033.49 Kcal/mol
Ir7+ -> Ir8+ = 10000 kJ/mol = 2392.34 Kcal/mol
Ir8+ -> Ir9+ = 11700 kJ/mol = 2799.04 Kcal/mol
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