Atomistry » Iridium » Chemical Properties » Ammonium Chloriridate
Atomistry »
  Iridium »
    Chemical Properties »
      Ammonium Chloriridate »

Ammonium Chloriridate, (NH4)2IrCl6

Ammonium Chloriridate, (NH4)2IrCl6, is readily produced by decomposing the sodium salt with ammonium chloride in aqueous solution. It crystallises in regular octahedra, reddish black in colour, and but slightly soluble in cold water, although appreciably soluble in hot. It does not dissolve in solutions of ammonium or potassium chloride. When evaporated with aqua regia, the ammonia is expelled, iridium tetrachloride remaining. Heated to 440° C. in a current of chlorine the tetrachloride is first formed and decomposes into the anhydrous trichloride.

Ammonium chloriridate is isomorphous with the corresponding chlorplatinate, (NH4)2PtCl6.

Its solubility in water is given as follows:

Temperature ° C14.426.839.452.261.269.3
Grams of (NH4)2IrCl6 per 100 grams solution0.6940.8991.1241.5832.0682.746


The solubility of the salt in water between these temperatures is given approximately by the expression:

Solubility = 0.680 + 0.0004t(t - 10).

Rubidium Chloriridate, Rb2IrCl6, is obtained by mixing a solution of iridium tetrachloride with excess of rubidium chloride, whereby a deep red, crystalline precipitate is obtained. The salt dissolves slightly in hot water to yield an orange-red solution.

Last articles

Hg in 2O1F
Hg in 2NNV
Hg in 2NNS
Hg in 2JHN
Hg in 2NNO
Hg in 2NNG
Hg in 2KT3
Hg in 2JLN
Hg in 2J4C
Hg in 2J4F
© Copyright 2008-2020 by atomistry.com
Home   |    Site Map   |    Copyright   |    Contact us   |    Privacy